ANSWER:
3.82 x 10^-9 N
Explanation:
Given:
Mass 1 (m1) = Mass 2 (m2) = 2.8 kg
Distance (d) = 0.37 m
According to Newton's laws of gravitation, the attractive force is given by the following expression:
![\begin{gathered} F=G\cdot(m_1\cdot m_2)/(d^2) \\ \\ G=6.67\cdot10⁻¹¹\text{ N*m^^b2/kg^^b2} \\ \\ \text{ We replacing:} \\ \\ F=6.67\cdot\:10^(-11)\cdot(2.8\cdot2.8)/(0.37^2) \\ \\ F=3.82\cdot10^(-9)N \end{gathered}]()
The magnitude of the gravitational attraction between the books is 3.82 x 10^-9 N