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IN . 110 1 time soch speed (mysed Create the equation for Line B in the graph and find the speed corresponding to the elapse time of zero? (10 Points)

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Let:


\begin{gathered} (v1,t1)=(0,60) \\ (v2,t2)=(20,50) \end{gathered}

So:


m=(t2-t1)/(v2-v1)=(50-60)/(20-0)=(-10)/(20)=-(1)/(2)

Using the point-slope equation:


\begin{gathered} t-t1=m(v-v1) \\ t-60=-(1)/(2)(v-0) \\ t-60=-(1)/(2)v \\ t(v)=-(1)/(2)+60 \end{gathered}

Since we have the equation now, let's find the speed corresponding to the elapse time of zero:


\begin{gathered} t(v)=0 \\ 0=-(1)/(2)v+60 \\ solve_{\text{ }}for_{\text{ }}v \\ -(1)/(2)v=-60 \\ v=-2\cdot(-60) \\ v=(120m)/(s) \end{gathered}

User Sensei James
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