Given:
![4x-3y=12](https://img.qammunity.org/2023/formulas/business/high-school/fh3rlardgb9z6ehmn9m7xoiv2th4lovmoh.png)
The y-intercept is the point where the line crosses the y-axis, at this point the x-coordinate is equal to zero. To find the corresponding y-coordinate, you have to replace the equation by x=0 and solve for y:
![\begin{gathered} 4x-3y=12 \\ 4\cdot0-3y=12 \\ 0-3y=12 \\ -3y=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/r9mz61d6vunydrr030lkg6h43arub8f64v.png)
Divide both sides by -3
![\begin{gathered} (-3y)/(-3)=(12)/(-3) \\ y=-4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/fl7pxfhzghz30ko3xlpz353dxzy1w537dv.png)
The y-intercept is (0,-4)
The x-intercept is the point where the line crosses the x-axis, at this point, the y-coordinate is zero. To find the x-coordinate of the x-intercept you have to replace the equation with y=0 and solve for x:
![\begin{gathered} 4x-3y=12 \\ 4x-3\cdot0=12 \\ 4x=12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/6sq9zrvzo0trd5l6sk4iylef1ubh4ds9cp.png)
Divide both sides by 4
![\begin{gathered} (4x)/(4)=(12)/(4) \\ x=3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/k7uk37jpg3idjrmithxtqs6wzp3jquwmoh.png)
The x-intercept is (3,0)