Question

ÐR is the right angle of D PQR. Write the following ratios.(i) sin P (ii) cos Q (iii) tan P (iv) tan Q

Answer 1

let x be the length of PR. Let y be the length of QR.

we get that the length of PQ is:

`z=\sqrt[]{x^2+y^2}`

so we get that:

`\sin P=(y)/(z),\cos Q=(y)/(z),\tan P=(y)/(x),\tan Q=(x)/(y)`