Question

Can you help me!

Determine the solution to the following one-variable linear equation:

a. 4a - 11 = 2a + 3
b. 3z + 12 = 15
c. 2 - 6b = 20
d. 3y - 5 = 27 - y​

Answer 1

♪Answer :

#A

• 4a - 11 = 2a + 3
• 4a - 2a = 3 + 11
• 2a = 14
• a = 14/2
• a = 7✅

#B

• 3z + 12 = 15
• 3z = 15 - 12
• 3z = 3
• z = 3/3
• z = 1✅

#C

• 2 - 6b = 20
• -6b = 20 - 2
• -6b = 18
• b = 18/(-6)
• b = -3✅

#D

• 3y - 5 = 27 - y
• 3y + y = 27 + 5
• 4y = 32
• y = 32/4
• y = 8✅

Answer 2

Hi,

4a - 11 = 2a + 3

4a - 11 + 11 = 2a + 3 + 11

4a = 2a +14

4a - 2a = 2a - 2a + 14

2a = 14

2a / 2 = 14 / 2

a = 7

3z + 12 = 15

3z + 12 - 12 = 15 - 12

3z = 3

3z / 3 = 3 / 3

z = 1

2 - 6b = 20

2 - 2 - 6b = 20 - 2

- 6b = 18

6b = - 18

6b / 6 = -18 / 6

b = -3

3y - 5 = 27 - y

3y - 5 + 5 = 27 - y + 5

3y = - y +32

3y + y = - y + y +32

4y = 32

4y / 4 = 32 / 4

y = 8

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