Given data:
* The mass of the Mangan is 86 kg.
* The friction force applied by the floor on the Mangan is 150 N.
Solution:
The normal force acting on the Mangan is,
![F_N=mg](https://img.qammunity.org/2023/formulas/physics/college/kzn42fx52oikk0s1ndjhmsze8oor55phgj.png)
where m is the mass of Mangan, and g is the acceleration due to gravity,
Substituting the known values,
![\begin{gathered} F_N=86*9.8 \\ F_N=842.8\text{ N} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/vibuo4ye3rpd05nximcuqqummrb0lrqsu1.png)
The friction force acting on the Mangan is,
![undefined]()