Given a table represents a linear relation between (x) and (y)
we will find the slope and the y-intercept
From the table, when x = -1, y = -4
and when x = 0, y = -3
We will find the slope as follows:
![slope=(y_2-y_1)/(x_2-x_1)=((-3)-(-4))/((0)-(-1))=(-3+4)/(0+1)=1](https://img.qammunity.org/2023/formulas/mathematics/college/dp1t789duq1dsg44tt4s148rv31aqe2voi.png)
And the y-intercept is the value of (y) when x = 0
So, the y-intercept = -3
So, the answer will be:
![\begin{gathered} slope=1 \\ y-intercept=(0,-3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3ahgtagr7qjci150ikd753wmnj1zwmhlld.png)