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Consider the following reversible reaction.Upper (s) plus upper O subscript 2 (g) double-headed arrow upper C upper O subscript 2 (g).What is the equilibrium constant expression for the given system?

Consider the following reversible reaction.Upper (s) plus upper O subscript 2 (g) double-example-1
User Chakra
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1 Answer

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Given the reaction:

C + O2 ⇄ CO2

We can find the equilibrium constant (Keq) using the following:


k_(eq)=([products])/([reactants])
k_(eq)=([products])/([reactants])\Rightarrow k_(eq)=([CO_2])/([C][O2])

Therefore the answer is letter A

User Haibara Ai
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