Question

What volume,expressed in liters,would 432.8 grams of fluorine occupy?

Answer 1

The volume of fluorine is 510.52L

Explanation:

From the question provided, you were given the mass of fluorine to be 432.8 grams.

Given information

Mass of fluorine = 432.8 grams

To find the volume of Fluorine, we need to find the mole of fluorine from the mole formula

`\text{Mole = }\frac{\text{ reacting mass}}{\text{ molar mass}}`

From the periodic table, the molar mass is 18.99 g/mol

The next thing is to substitute the data into the formula

`\begin{gathered} \text{Mole = }\frac{\text{ 432.8}}{18.99} \\ \text{Mole = }22.79\text{ moles} \end{gathered}`

Since the mole of fluorine is 22.79 moles, then, we can now find the volume of fluorine.

At STP, 1 mole is equivalent to 22.4L

Let the volume of fluorine be x

`\begin{gathered} 1\text{ mole }\rightarrow\text{ 22.4L} \\ 22.79\text{ moles }\rightarrow\text{ xL} \\ \text{Cross multiply} \\ 1\cdot\text{ x = 22.4 }\cdot\text{ 22.79} \\ x\text{ = 510.52L} \end{gathered}`

The volume of fluorine is 510.52L