Question

The General Sherma, the largest tree in the world, has a maximum diameter of 36.5 feet. What is the circumference of the tree?

Answer 1

The circumference of the General Sherman, the largest tree in the world with a max diameter of 36.5 feet, can be calculated using the formula C = πd and is approximately 114.65 feet.

Step-by-step explanation:

To find the circumference of the General Sherman, which is the largest tree in the world with a maximum diameter of 36.5 feet, we can use the formula for the circumference of a circle, which is C = πd, where 'π' represents Pi (approximately 3.14159) and 'd' is the diameter. Substituting the given diameter:

C = π × 36.5 feet

C = 3.14159 × 36.5 feet

C ≈ 114.65 feet

The circumference of the General Sherman tree is approximately 114.65 feet.

Answer 2

The General Sherman Tree is the world's largest tree, measured by volume. It stands 275 feet (83 m) tall and is over 36 feet (11 m) in diameter at the base. Sequoia trunks remain wide high up. Sixty feet above the base, the Sherman Tree is 17.5 feet (5.3 m) in diameter.

Step-by-step explanation: