Find the area of the surface generated by revolving x = t y = t^2 1 ≤ t ≤ 2 around the y-axis

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Linus Oleander asked May 26, 2022

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Find the area of the surface generated by revolving x = t y = t^2 1 ≤ t ≤ 2 around the y-axis

Mathematics
high-school

Linus Oleander asked May 26, 2022

by Linus Oleander

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27 votes

answer is 4^22x (sorry it’s late)

Emily Kothe answered May 27, 2022

by Emily Kothe

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12 votes

Answer:

4^22x

Explanation:

Dvdhns answered Jun 1, 2022

by Dvdhns

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