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3 votes
3 votes
Find the area of the surface generated by revolving x = t y = t^2 1 ≤ t ≤ 2 around the y-axis

User Linus Oleander
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2 Answers

27 votes
27 votes
answer is 4^22x (sorry it’s late)
User Emily Kothe
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12 votes
12 votes

Answer:

4^22x

Explanation:

User Dvdhns
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