Question

Ms. Lee bought some Reese's and a bag of chips. They cost $4.36 altogether. The chips cost $1.60 more than the Reese's.How much did the Reese's cost? (Hint: it's not as simple as subtracting the two numbers)

Answer 1

Let x be the price of the reese's. Since we know that the chips cost $1.6 more that means that its price is:

`x+1.6`

Now, both things had a cost of 4.36, then we have:

`x+(x+1.6)=4.36`

Solving for x we have:

`\begin{gathered} x+(x+1.6)=4.36 \\ 2x+1.6=4.36 \\ 2x=4.36-1.6 \\ 2x=2.76 \\ x=(2.76)/(2) \\ x=1.38 \end{gathered}`

Therefore the cost of the reese's is $1.38.