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How many litres of gas is there in 3.55x10^6 mol Ne at STP

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We assume ideal gas conditions, and we have here STP conditions, so:

1 mol of Ne = 22.4 L (STP)

Procedure:

1 mol Ne -------- 22.4 L

3.55x10^6 moles ------- X

X = 8.0x10^7 L Ne (approx.)

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