Question

Please walk me through so I can get a better understanding please

Answer 1

From the given figure we can see

1. A-line with a negative slope intersects the y-axis at (0, 1)

It has a closed-end at x = 1

Its slope is -2

Then its equation is

`y=-2x+1,x\leq1`

2. A-line with a negative slope intersects the x-axis at (2, 0)

It has an open-end at x = 1

Its slope is -1

Then its equation is

`y=-x+2,x>1`

Then the answer is

`y=\begin{cases}{-2x+1,x\leq1} \\ {-x+2,x>1} \\ {}\end{cases}`

The answer is a