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F(x)=x^3 −9x
What is the average rate of change of f over the interval [1,6] ?

User Hyuan
by
6.2k points

1 Answer

3 votes

Answer:34

Explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

Here [ a, b ] = [ 1, 6 ], thus

f(b) = f(6) = 6³ - 9(6) = 216 - 54 = 162

f(a) = f(1) = 1³ - 9(1) = 1 - 9 = - 8

average rate of change = = = 34

User Mark Pruce
by
6.1k points
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