Question

The period of a .75 m pendulum is _s

Answer 1

Hi there!

We can use the following equation for the period of a pendulum:

`\large\boxed{T = 2\pi \sqrt{(L)/(g)}}`

T = Period (s)
L = length of simple pendulum (.75 m)

g = acceleration due to gravity (9.8 m/s²)

Plug in the values:

`T = 2\pi \sqrt{(.75)/(9.8)} = \boxed{1.738 s}`