Question

Let P(x) = (u^x (e^-u))/x! and let u = 8. Find P(0)(Round to six decimal places as needed.)

Answer 1

P(x) = (u^x (e^-u))/x!

If u= 8 then

P(0) = (u^0• (e^-8))/ 1

Then, answer is

P(0) = e^-8 = 3.354644. x 10^-4