To graph this linear function, we can use the x- and the y-intercepts of the function. To achieve this, we can proceed as follows:
1. Finding the x-intercept of the line
The x-intercept is the point where the function passes through the x-axis and at this point the value for y = 0. Then, the x-intercept is:
![3x-2y=-12\Rightarrow y=0\Rightarrow3x-2(0)=-12](https://img.qammunity.org/2023/formulas/mathematics/college/1zpsyqwux1ajdn600rrqphpq0kr1pbd2p3.png)
Then, we have:
![3x=-12\Rightarrow(3x)/(3)=-(12)/(3)\Rightarrow x=-4](https://img.qammunity.org/2023/formulas/mathematics/college/o4rj4ek5wpcgwkyk4lxiw0dd3hzxua6ds8.png)
Then, the x-intercept is (-4, 0). See that it is easier to identify this point on the coordinate to graph the function.
2. Finding the y-intercept
In this case, we need to find the value of y when x = 0. The y-intercept is the point where the linear function passes through the y-axis. Then, we have:
![3x-2y=-12\Rightarrow x=0\Rightarrow3(0)-2y=-12](https://img.qammunity.org/2023/formulas/mathematics/college/o1o3hnutf5pxif1v4ztqsffoboac62nna8.png)
Then, we can divide both sides of the equation by -2:
![-2y=-12\Rightarrow-(2y)/(-2)=-(12)/(-2)\Rightarrow y=6](https://img.qammunity.org/2023/formulas/mathematics/college/obtqmoqm6js0alanxzkh7q2zjjadljn1lv.png)
Then, the y-intercept is (0, 6).
3. Finding the slope of the line
We can rewrite the line equation given in the standard form into the slope-intercept form as follows:
The slope-intercept form of the line is:
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
Where
• m is the slope of a line.
,
• b is the y-intercept of the line.
Then, we have:
![3x-2y=-12](https://img.qammunity.org/2023/formulas/mathematics/college/l8toy8eja3wu4j6f0stp9lhwm01m76s1tn.png)
To solve the equation for y, we can follow the next steps:
1. Subtract 3x to both sides of the equation:
![3x-3x-2y=-12-3x\Rightarrow-2y=-12-3x](https://img.qammunity.org/2023/formulas/mathematics/college/849ipm1hd0dupxa41u3yudvs6p4mv0ve4z.png)
2. Divide both sides of the equation by -2:
![-(2y)/(-2)=-(12)/(-2)-(3)/(-2)x\Rightarrow y=6+(3)/(2)x\Rightarrow y=(3)/(2)x+6](https://img.qammunity.org/2023/formulas/mathematics/college/xjqz1owoey7k6t2zehy3l301ax3a0ew9fd.png)
Then, the slope of this line is m = 3/2.
With all of this information, we can answer the question about the attributes:
1. Domain
The domain of the function is, in interval form, as (-∞, ∞). That is the values for x are for all the values of x.
2. Range
The range of the linear function is for values of y from -∞ to ∞, or in interval form as (-∞, ∞).
We can see this if we graph the function as follows (we can graph the function by using the intercepts we found above):
3. Zero
The zero of the function is the point for which the function is equal to zero, and we found that this point is the same as the x-intercept. The zero of the function is x = -4, because:
![f(-4)=(3)/(2)(-4)+6=3(-2)+6=-6+6=0](https://img.qammunity.org/2023/formulas/mathematics/college/ibk9h9v20075ofrcj1mpcwi6g3pl94ytyf.png)
4. The Y-intercept
We already found that the y-intercept is (0, 6).
5. The slope of the line
We already found the slope of the line: m = 3/2.
6. Type of slope
The slope of the line is a positive slope.
7. The value of the linear function when f(0)
To find this value, we need to substitute the value of x = 0 into the line equation as follows (the result will be the y-intercept):
![y=f(x)=(3)/(2)x+6\Rightarrow f(0)=(3)/(2)(0)+6\Rightarrow f(0)=6](https://img.qammunity.org/2023/formulas/mathematics/college/lan12hzjx8sxnh6aiv1lyki75xrardr0th.png)
Then, f(0) = 6.
8. The value of x, where f(x) = 0
We already found this value. The value of x for which the function is zero is x = -4 (see above).
Therefore, in summary, we have: