![48\:apartments\:in\:9\:hours](https://img.qammunity.org/2023/formulas/mathematics/college/qvup7w78p173u2mplcp2crvo8jmbqyzu60.png)
1) In this problem, the first thing to do is to enlist the categories:
workers time to clean # apartments
8 2h15 12
8 9 x
2) Note that the number of cleaners is the same. So, we can pick the ratios that fall under the category time and #apartments
We need to convert that 2h 15 into decimal form before setting the ratios:
![2h15\:2+(15)/(60)=2.25](https://img.qammunity.org/2023/formulas/mathematics/college/6ek7m0q3l8rhit5smrbrfdg2iic4wx2btl.png)
3) Now, we can set the ratios and solve for x:
![\begin{gathered} (2.25)/(9)=(12)/(x) \\ 2.25x=12\cdot9 \\ (2.25x)/(2.25)=(108)/(2.25) \\ x=48 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/vp0ei2gp46h990k56jhxohq4onucsrzhmq.png)
Thus, the answer is 48