Question

Write a function that crosses the x-axis at x = 3 and x=-2, and bounces off the x-axis at x = 5.

Answer 1

We have 2 crossings at x=3 and x=-2. Then, the factors (x-3) and (x+2) have degree one. On the other hand, since the function bounces off at x=5, the exponent of the factor (x-5) has to be even. So, we can write our function as

`f(x)=A(x-3)(x+2)(x-5)^n`

where A is the leading coefficient and n is a even number: 2, 4, 6, 8, .... etc.