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Factor P (x) into linear factors given that k is a zero of P.
P(x) = x³- 2x² - 7x - 4 ; k = -1

Factor P (x) into linear factors given that k is a zero of P. P(x) = x³- 2x² - 7x-example-1

1 Answer

5 votes

Answer:

P(x) = (x +1)²(x -4)

Explanation:

You want the complete factorization of P(x) = x³- 2x² - 7x - 4.

Graph

A graph of the function is attached. It verifies that (x-k) = (x +1) is a factor, with multiplicity 2, and shows that (x -4) is also a factor.

P(x) = (x +1)²(x -4)

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Additional comment

If P(x) has a zero at x=k, then (x -k) is a factor.

If the graph does not cross the x-axis at a zero, then that zero has even multiplicity.

Here, the cubic must have (at most) 3 real zeros, so there must be two others in addition to the one at x=4. That means the multiplicity of the zero at x=-1 is 2, and the factorization is ...

P(x) = (x +1)(x +1)(x -4)

We could determine the factorization by dividing P(x) by (x+1) to get a quotient of x²-3x-4. The factors of this quadratic are (x +1)(x -4), so the complete factorization is as shown above. The division could be by polynomial long division, or by synthetic division (shown in the second attachment).

Factor P (x) into linear factors given that k is a zero of P. P(x) = x³- 2x² - 7x-example-1
Factor P (x) into linear factors given that k is a zero of P. P(x) = x³- 2x² - 7x-example-2
User James Montagne
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