Answer:
f(x) = x^2
Explanation:
Any quadratic (2nd-degree) function will have 0 as its third derivative.
f(x) = ax² +bx +c
f'(x) = 2ax +b
f''(x) = 2a
f'''(x) = 0
Perhaps the simplest such function is f(x) = x^2.
1.6m questions
2.0m answers