Question

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The figure below shows three edge views of a square loop with sides of length ℓ = 0.240 m in a magnetic field of magnitude 1.25 T. Calculate the magnetic flux (in Wb) through the loop oriented perpendicular to the magnetic field, 60.0° from the magnetic field, and parallel to the magnetic field.


(a) perpendicular to the magnetic field? _____Wb

(b) 60.0° from the magnetic field? ____Wb

(c) parallel to the magnetic field? _____Wb

Answer 1

0.072, 0.062, 0

Step-by-step explanation:

Flux = magnetic field B * area A * cos(angle between B and normal of A)

= 1.25 * 0.24^2 * cos(angle) = 0.072 * cos(angle)

a) angle = 0°, flux = 0.072 Wb

b) angle = 30°, flux = 0.072*cos(30) = 0.062 Wb.

c) angle = 90°, flux = 0