Hint: Tetrafluoromethane, otherwise called carbon tetrafluoride or R−14
, is the most straightforward perfluorocarbon (CF4
). As its IUPAC name shows, tetrafluoromethane is the per fluorinated partner to the hydrocarbon methane. It can likewise be named a haloalkane or halomethane.
Complete step by step answer:
On the off chance that you take a gander at the condition, you will see that for each one mole of C
that is responded, one mole of CF4
is delivered. Thus, 1.46
moles of CF4
are created (expecting that there is sufficient F2
). A mole of CF4
has a mass of around 88
grams, so 1.46
moles is equivalent to 128.48
grams. Adjusted to critical figures, your answer will be 128
grams.
Let’s do it bit by bit:
First Change moles of carbon to moles of CF4
n(CF4)=1.46 mol C × (1 mol CF41 mol C) = 1.46 mol CF4
At that point convert moles of CF4
to grams of CF4
utilizing the molar mass
M(CF4)=(1×12+4×19)gmol−1=88gmol−1
m(CF4)=nM=1.46mol×88gmol−1=128g
So, the required answer is [128g]