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Find the equation of a line parallel to 3y = -30 - 3x that passes through the point (-6, -1)

User ZiMtyth
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1 Answer

3 votes

Answer:

y= -x-7

Explanation:

1. we want to make the equation 3y= -30-3x in the form of y=mx+c

therefore, we divide each side by 3 this gives us

y= -10-x (we can also write that as y= -x-10)

2. From this we can tell that the gradient is -1 (the coefficient of x or also known as the value of m in y=mx+c)

3. we also know the line passes through the points (-6,-1) therefore

x= -6 and y=-1

4. we know the value of m, x, and y so we can substitute it in y=mx+c to find the value of c

y=mx+c

-1= -1(-6)+c

-1 =6+c (we -6 on both sides to get c on its own)

-7=c (so c=-7) (c is also known as y intercept)

5. Know we can sub in the value of m and c in the equation y=mx+c to get our final equation which is

y= -x-7

User Grief
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