Question

Question 1 of 10

What is the equation of the parabola in vertex form?
0=y²-x-4y+3
O A. (x-3)=(y-2)²
O B. (x+12)2 = (y-4)
O c. (x+1)=(y-2)²
O D. (x-1)= (y + 2)²

Answer 1

3(r+2s)=2t−4

Use the distributive property to multiply 3 by r+2s.

3r+6s=2t−4

Subtract 6s from both sides.

3r=2t−4−6s

The equation is in standard form.

3r=−6s+2t−4

Divide both sides by 3.

3

3r

​

=

3

−6s+2t−4

​

Dividing by 3 undoes the multiplication by 3.

r=

3

−6s+2t−4

​

Divide −4+2t−6s by 3.

r=

3

2t

​

−2s−

3

4

​

SOLVE FOR S