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Write the equation of the line that passes through (5,-2) and is perpendicular to y = 5/3x-3.

y= -3/5 x +1

y= -3/5x + 19/5

y= 3/5 x -5

y= 3/5 x - 31/3

1 Answer

3 votes

Explanation:

the slope (a) is always the factor of x in an equation

y = ax + b

it is the ratio (y coordinate difference / x coordinate difference) when going from one point on the line to another.

a perpendicular slope now turns this ratio fraction upside-down and flips the sign.

so, the perpendicular slope of 5/3 is -3/5.

therefore, the last 2 answer options are out.

we have the equation

y = -3/5 x + b

now we use the coordinates of the given point to find b.

-2 = -3/5 × 5 + b = -3 + b

1 = b

so, the correct equation is

y = -3/5 + 1

User Adnane
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