Question

After playing the "Spin to Win" game, which has a probability of 0.25 of winning on any individual spin, Nick decides

to play "Knock down the Bottles." To win, Nick has to knock down all 3 bottles. Nick determines that the probability of
winning this game is 0.8. Nick plays "Spin to Win" twice and then plays "Knock down the Bottles" twice.
What is the probability that Nick loses both times he plays "Spin to Win" and wins both times he plays "Knock down
the Bottles"?
O 0.04
O 0.0025
O 0.0225
O 0.36

Answer 1

The probability that Nick loses both 'Spin to Win' games and wins both 'Knock down the Bottles' games is 0.36.

Step-by-step explanation:

To calculate the probability that Nick loses both times he plays 'Spin to Win' and wins both times he plays 'Knock down the Bottles', we need to consider each event as independent and multiply their probabilities. The probability of losing 'Spin to Win' is 1 - 0.25 = 0.75 since there's a 0.25 chance of winning. Therefore, the probability of losing twice is 0.75 x 0.75. Likewise, the probability of winning 'Knock down the Bottles' is given as 0.8, so the probability of winning twice is 0.8 x 0.8.

By multiplying these probabilities together, we get:

(0.75 x 0.75) x (0.8 x 0.8) = 0.5625 x 0.64 = 0.36

Thus, the probability that Nick loses both times on 'Spin to Win' and wins both times on 'Knock down the Bottles' is 0.36.

Answer 2

0.36

Step-by-step explanation:

Edge 2021