Question

What is an equation of the line that passes through the points (-4, -2) and (-8, 3)?

Answer 1

find the gradient of the line -

3 - -2/ -8-4 = 5/-12

then sub this value into y=mx+c

y=(5/-12)x + c

then sub in one of the given coordinates

3 = (5/-12)(-8) + c

c= 3/ (5/-12 x -8)

Answer 2

`y = -\frac54x -7`

Explanation:

Slope:

• 
  `(3 - (-2))/(-8 - (-4))`
• 
  `-(5)/(4)`

Y-intercept:

• 
  `y = -\frac54x + b\\`
• 
  `-2 = -\frac54(-4) + b`
• 
  `-2 = 5 + b`
• 
  `b=-7`

y = -5/4x -7

-Chetan K