Question

Find an equation for the line points of (-4, -5) and (6, 1)

Answer 1

In order to find the equation, let's use the slope-intercept form of the linear equation:

`y=mx+b`

Where m is the slope and b is the y-intercept.

Using the points (-4, -5) and (6, 1), we can calculate the values of m and b:

`\begin{gathered} (-4,-5)\colon \\ -5=-4m+b\to b=4m-5 \\ \\ (6,1)\colon \\ 1=6m+b \\ 1=6m+4m-5 \\ 10m-5=1 \\ 10m=1+5 \\ 10m=6 \\ m=(6)/(10)=(3)/(5) \\ \\ b=4\cdot((3)/(5))-5=(12)/(5)-(25)/(5)=(-13)/(5) \\ \\ y=(3)/(5)x-(13)/(5) \end{gathered}`