Question

6. A sample of carbon dioxide occupies 45 L at 750 K and 2800 mmHg. What is he volume of the gas at STP (0 °C and 1atm)?

Answer 1

`V_2\text{ = 60.38 L}`

Step-by-step explanation:

Here, we want to get the volume of the gas at STP

According to the general gas law, we have it that:

`(P_1V_1)/(T_1)\text{ = }(P_2V_2)/(T_2)`

where:

P1 is the initial pressure which is 280 mmHg

V1 is the initial volume which is 45 L

T1 is the initial temperature which is 750 K

P2 is the final pressure which is 1 atm (760 mmHg)

V2 is the volume that we want to calculate

T2 is the final temperature (0 degrees celsius is 273.15 K)

Substituting the values, we have it that:

`\begin{gathered} (2800*45)/(750)\text{ = }(760* V_2)/(273.15) \\ \\ V_2\text{ = }(2800*45*273.15)/(760*750)\text{ = 60.38 L} \end{gathered}`