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CorrectSolve the following system of linear equations by graphing:- 8x + 4y = 12- 10x + 5y = -10Anu

User Elba
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4-2-To solve this problem we have to graph the functions so we have to find two points of each equations so for the first one:

if x=0


\begin{gathered} -8(0)+4y=12 \\ 4y=12 \\ y=(12)/(4) \\ y=3 \end{gathered}

Now for y=0


\begin{gathered} -8(x)+4(0)=12 \\ x=(12)/(-8) \\ x=-1.5 \end{gathered}

So the two coordinates of the first equation are (0, 3) and (-1.5, 0)

Now for the secon equation for x=0


\begin{gathered} -10(0)+5y=-10 \\ y=-(10)/(5) \\ y=2 \end{gathered}

And for y=0


\begin{gathered} -10(x)+5(0)=-10 \\ x=(-10)/(-10) \\ x=1 \end{gathered}

So the coordinates are: (0, 2) and (1, 0) So now we can graph the line and the solution will be the point where they intercept so:

The solution is mor o less (-0.5 , 2.5)

CorrectSolve the following system of linear equations by graphing:- 8x + 4y = 12- 10x-example-1
User WAQ
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