Part 1
Find out the area
The area of the given figure is equal to the area of a square of 6 x 6 units, minus the area of four right triangles of dimensions 3 x 3
so
![A=6^2-4\cdot\lbrack(1)/(2)\cdot(3)\cdot(3)\rbrack](https://img.qammunity.org/2023/formulas/mathematics/college/uze5n467azmu9q71tmljp457b8rsksysh9.png)
![\begin{gathered} A=36-18 \\ A=18\text{ unit2} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ous5ue2easfolc11yi54mm5q6dq8ky3m0q.png)
the area is 18 square units
Part 2
Find out the perimeter
The perimeter of the figure is equal to the hypotenuse of the right triangle (3 x 3 units) multiplied by 4
therefore
![\begin{gathered} P=4\cdot\lbrack\sqrt[]{18}\rbrack \\ P=4\sqrt[]{18\text{ }}units \\ P=12\sqrt[]{2}\text{ units} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/2hgd6bldjobrowci2zk8nqkyteq2boerd0.png)
the perimeter is 16.97 units