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Hello, I need help with this last practice problem. Thank you!

Hello, I need help with this last practice problem. Thank you!-example-1
User Wiesson
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1 Answer

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Answer:

Neither

Parallel

Neither

Parallel lines have the same slope while Perpendicular lines have slopes that are the negative reciprocals of each other.

Let us check the relation between lines 1 and 2:


\begin{gathered} 6x+3y=12 \\ y=2x+1 \end{gathered}

First, we rewrite and simplify line 1 into its slope-intercept form.


\begin{gathered} 6x+3y=12 \\ \Rightarrow3y=-6x+12 \\ \Rightarrow y=-2x+4 \end{gathered}

We now have the lines


\begin{gathered} y=-2x+4 \\ y=2x+1 \end{gathered}

Since they do not have the same slope and the slopes are not the negative reciprocals of each other, Lines 1 and 2 are neither parallel nor perpendicular.

Next, in Lines 1 and 3, we have:


\begin{gathered} y=-2x+4 \\ y=-2x-7 \end{gathered}

Since they have the same slope, these lines are parallel lines.

Lastly, we have lines 2 and 3. We have:


\begin{gathered} y=2x+1 \\ y=-2x-7 \end{gathered}

Just like lines 1 and 2, since they do not have the same solution and are not the negative reciprocal of each other, lines 2 and 3 are neither parallel nor perpendicular lines.

User Mercador
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