Question

6. Refer to the following unbalanced equation: CH14 + 02 → CO2 + H2O

What mass of oxygen (O2) is required to react completely with 21.4 g of C6H14?

Answer 1

To react completely with 21.4 g of C6H14, 55.52 g of oxygen (O2) is required.

Step-by-step explanation:

To find the mass of oxygen (O2) required to react completely with 21.4 g of C6H14, we need to use the balanced chemical equation: CH14 + 02 → CO2 + H2O

From the equation, we can see that 1 mole of C6H14 reacts with 7 moles of O2. Using the molar mass of C6H14 (86.18 g/mol) and the molar mass of O2 (32 g/mol), we can calculate the moles of C6H14 and then convert it to moles of O2. Finally, we can convert moles of O2 to grams using the molar mass of O2.

The calculation would be as follows:

• Calculate moles of C6H14: 21.4 g C6H14 / 86.18 g/mol = 0.248 mol C6H14
• Calculate moles of O2: 0.248 mol C6H14 x 7 mol O2 / 1 mol C6H14 = 1.736 mol O2
• Calculate grams of O2: 1.736 mol O2 x 32 g/mol = 55.52 g O2