How can i solve this provelm and round it to the nearest thenth of a centimeter

asked Nov 17, 2023 14.2k views

0 votes

by Nya

4.2k points

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7 votes

Applying Pythagoras' theorem;

$hypotenuse^2=\text{ x}^2+y^2$
158^2=83^2+z^2

$\begin{gathered} 24964=6889+z^2 \\ z^2=24964-6889 \\ z^2=18075 \\ z=√(18075) \\ z=134.4cn \end{gathered}$

Wasd answered Nov 22, 2023

by Wasd

4.7k points

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