Answer:
D) 2(4+x)=8+2x
Step-by-step explanation:
To be able to determine which of the equations has infinitely many solutions, let's go ahead and solve for x in each of the equations. The equation with infinitely many solutions will have zero on both sides.
1. 5x - 10 = x + 20, to solve for x;
![\begin{gathered} 5x+x=20+10 \\ 6x=30 \\ x=(30)/(6)=5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gwigvk2bgbs0l8e7nph7i1vsjqpl2oaycz.png)
From the solution, x = 5, we can see that this isn't the right option.
2. 2(6+x)=14+2x, let's solve for x;
![\begin{gathered} 12+2x=14+2x \\ 2x-2x=14-12 \\ 0=2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/brv2ggu2vvruxjjeyi1ocx4qsqyvvh6x6s.png)
This too isn't the correct option.
3. 10x+5=3(5x+7)
To solve for x;
![\begin{gathered} 10x+5=15x+21 \\ 10x-15x=21-5 \\ -5x=16 \\ x=(16)/(-5)=-3.2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1b6bejl5xp0k4w4dagbnlksjdw97lt9yjm.png)
This isn't the correct option too.
4. 2(4+x)=8+2x
Let's solve for x;
![\begin{gathered} 8+2x=8+2x \\ 2x-2x=8-8 \\ 0=0 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/qca2vpfkuv0esk5hhl7d1rxalmdhmx8kfw.png)
We see from the solution that this is the equation with infinitely many solutions.