Question

Find the measure of the base angle of an isosceles triangle (to the nearest whole degree) with a leg that is 54 cm long and a base 66 cm long.

Answer 1

`\begin{gathered} \cos (\theta)=(33)/(54) \\ \\ \theta=\cos ^(-1)((33)/(54)) \\ \\ \theta=\text{ 52.33} \\ \text{The base angle is 52.33\degree} \\ \\ \text{when there are two sides with the same lenght in second type of triangle isosceles} \\ \text{hypotenuse =}\sqrt[]{2}\cdot54 \\ \text{hypotenuse =76.4} \\ \text{76.4}\\e\text{ 66 that is the why the triangles is not the second type} \\ \\ \cos \theta=\frac{\text{adjac}ent}{hypotenuse} \\ \\ \theta=\cos ^(-1)(\frac{\text{adjac}ent}{hypotenuse}) \end{gathered}`