We are given the following information.
Resistor: R₁ = 50 Ω
Resistor: R₂ = 100 Ω
We are asked to find the equivalent resistance of this circuit.
Notice that the resistors R₁ and R₂ are in series.
So, their equivalent resistance will be the sum of the individual resistors.
![\begin{gathered} R_(eq)=R_1+R_2 \\ R_(eq)=50+100 \\ R_(eq)=150\;\Omega \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/2vrjf3iex5vzmjwxmu01erolz2btng8819.png)
Therefore, the equivalent resistance of this circuit is 150 Ω.