Question

Given a geometric sequence of 2, 12, 72, and 432, what is the common ratio?a) 2b)6c)12d)72

Answer 1

Given that,

a geometric sequence of 2, 12, 72, and 432

To find the common ratio.

we know that, common ratio as,

`r=(t_n)/(t_(n-1))`

where tn is the nth term of the sequence.

Using this we get,

`r=(12)/(2)`
`r=6`

Common ratio is 6

Answer is: option (b): 6