Question

A circular loop with a radius of 15 cm is positioned in various orientations in a uniform magnetic field of 0.15 T. Find the magnetic flux if the normal to the plane of the loop is perpendicular to the field.

Answer 1

The magnetic flux of a uniform field B over a flat surface with area A and normal vector n is:

`\Phi=AB\cos\theta`

Where θ is the angle between the normal vector n and the direction of B.

If the normal to the plane of the loop is perpendicular to the field, then θ=90º:

`\Phi=AB\cos(90º)=AB\cdot0=0`

Therefore, the magnetic flux is 0.