EXPLANATION
Given the ordered pairs: J(-3,11) and K(1,-3), to calculate the equation of the line we use the following expression:
y= mx + b
First, we need to calculate the slope in this way:
![\text{Slope = }((y2-y1))/((x2-x1))=((-3-11))/((1-(-3)))=((-14))/((4))=-(7)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/fubkkikkjbbvvbzauwy08afgr6sfwfu1hn.png)
With this slope-value we take either one ordered pair and calculate b-value:
![11\text{ = -}(7)/(2)(-3)+b](https://img.qammunity.org/2023/formulas/mathematics/college/f7q85tui4loxalez9zi9mc8jbmq31w32eb.png)
Simplifying:
![11\text{ = }\frac{\text{21}}{2}+b](https://img.qammunity.org/2023/formulas/mathematics/college/9u21lfaqfwjibnzqvjv74x59pvl8a9i5fm.png)
Isolating b:
![b\text{ = 11 - }(21)/(2)\text{ = }\frac{\text{1}}{2}](https://img.qammunity.org/2023/formulas/mathematics/college/ox67lt9ljwb0bq4wa7aakm6fu2y86h1cdu.png)
Then, the equation will be:
![y\text{ = -}(7)/(2)x+(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/96fk6aglvzf2ept5vykfebdepsu1ac9iw2.png)
The standard form will be:
![(7)/(2)x+y\text{ = }(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/rzchwb6soamsb76jpeuc9ctobz4kc3ayb8.png)
Multiplying both sides by 2:
![7x+2y\text{ = 1}](https://img.qammunity.org/2023/formulas/mathematics/college/wput7ilv5ok2s19kuaurhbcerio6x0ck1h.png)
ANSWER is B) 7x + 2y = 1