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Lion JK passes through points J -3, 11 and K1, -3 what is the equation of the lien standard form

Lion JK passes through points J -3, 11 and K1, -3 what is the equation of the lien-example-1
User Nandun
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1 Answer

1 vote

EXPLANATION

Given the ordered pairs: J(-3,11) and K(1,-3), to calculate the equation of the line we use the following expression:

y= mx + b

First, we need to calculate the slope in this way:


\text{Slope = }((y2-y1))/((x2-x1))=((-3-11))/((1-(-3)))=((-14))/((4))=-(7)/(2)

With this slope-value we take either one ordered pair and calculate b-value:


11\text{ = -}(7)/(2)(-3)+b

Simplifying:


11\text{ = }\frac{\text{21}}{2}+b

Isolating b:


b\text{ = 11 - }(21)/(2)\text{ = }\frac{\text{1}}{2}

Then, the equation will be:


y\text{ = -}(7)/(2)x+(1)/(2)

The standard form will be:


(7)/(2)x+y\text{ = }(1)/(2)

Multiplying both sides by 2:


7x+2y\text{ = 1}

ANSWER is B) 7x + 2y = 1

User Jared Harding
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