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H(t) = -16t^2 +32t+ 48

1 Answer

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Given h(t ) = - 16t^2 + 3 2 t + 48

Divide through by 16,

-t^2 + 2t + 3 =0

Re-arranging, we have:

t^2 - 2t - 3 = 0,

t ^ 2 + t - 3t - 3= 0

t ( t + 1 ) - 3 ( t + 1) = 0

( t + 1 ) ( t - 3 ) = 0.

t + 1 = 0 or t - 3 = 0

t = -1 or t = 3

User Varun Verma
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