Question

Solve using substitution. y=103x + 4y = 19

Answer 1

We want to find the solutions for the following system

`\begin{cases}y=10 \\ 3x+4y=19\end{cases}`

We already know the value for the y variable, if we substitute this value on the second equation it is possible to find the x value.

`\begin{gathered} 3x+4\cdot(10)=19 \\ 3x+40=19 \\ 3x=19-40 \\ 3x=-21 \\ x=(-21)/(3) \\ x=-7 \end{gathered}`

And those are the results for our system

`\begin{cases}x=-7 \\ y=10\end{cases}`