The cosine of an angle theta in a right triangle is given by its adjacent side divided by the hypotenuse:

We don't know the value of r but with x, y and the Pythagorean Theorem we can find it:
![\begin{gathered} r=\sqrt[]{x^2+y^2}=\sqrt[]{3^2+6^2}=\sqrt[]{9+36}=\sqrt[]{45} \\ r=6.71 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/n4wa83ncm93but9m9q7vy3nm9p7lpkh3by.png)
Then the cosine we are looking for is:

Then the correct option is the second one since:
![\frac{\sqrt[]{5}}{5}=0.45](https://img.qammunity.org/2023/formulas/mathematics/college/nme2w6v542f8khli5fcgofsg3ycrngzlyw.png)