Question

What is an equation of the line that passes through the points (-6, 5) and (6, 7)?

Answer 1

`y=(1)/(6)x+6`

Explanation:

Let
`(x_1,y_1)\rightarrow(-6,5)` and
`(x_2,y_2)\rightarrow(6,7)`

Determine slope

`m=(y_2-y_1)/(x_2-x_1)\\ \\m=(7-5)/(6-(-6))\\ \\m=(2)/(6+6)\\ \\m=(2)/(12)\\ \\m=(1)/(6)`

Use either ordered pair to find the y-intercept

`y=mx+b\\\\7=(1)/(6)(6)+b\\\\7=1+b\\\\6=b`

Final equation

`y=(1)/(6)x+6`