![a)(1)/(2)b)(5)/(6)c)(5)/(6)d)(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/bvq38hasxvkukmgafgm1sgdf08fb0sdbxh.png)
1) Considering that a six-sided dice has all these possible numbers as outcomes we can write our sample space:
![1,2,3,4,5,6](https://img.qammunity.org/2023/formulas/mathematics/college/9l0epgkcot4p4919wfoynrnge1uhlpkic8.png)
2) So let's calculate the Probabilities:
a) Even number.
Note that we have three even numbers
![1,\mathbf{2},3,\mathbf{4},5,\mathbf{6}](https://img.qammunity.org/2023/formulas/mathematics/college/5o4vc9gz8parlrmaj8amr8nt8m6mqb5fph.png)
So we can write the Probability of Even numbers as:
![P(\text{even)}=(3)/(6)=(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/zptsefoec0iifk1w9jmjw5m8h62x0cqj0v.png)
Note that on the denominator, we place the total possible results, and on the numerator the favorable outcomes.
b) A number > 1
Since we've got 5 favorable events (numbers) greater than 1, we can write out:
![P(>1)=(5)/(6)](https://img.qammunity.org/2023/formulas/mathematics/college/1dxbpibx8mgxi0mfxpubo8t5a6vmtzynrn.png)
c) A number < 6
![P(<6)=(5)/(6)](https://img.qammunity.org/2023/formulas/mathematics/college/iwts3t0ydkduzfy89zdk5adeogkefndgng.png)
Note that similarly to the previous item we have 5 favorable outcomes (1,2,3,4,5) in a total of 6 possible results.
d) A Prime number:
In a six-sided die we have the following prime numbers:
![\mathbf{2},\mathbf{3},4,\mathbf{5},6](https://img.qammunity.org/2023/formulas/mathematics/college/zu5sg3c8vsz3ppsp6557evtodv0txrvek0.png)
So we have 3 favorable outcomes:
![P(\text{prime)}=(3)/(6)=(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/xkm0405jn8r2a6qoa5iezoludd4tn7alkn.png)
And that is the answer