Question

Rewrite logsub11 38 as a base 10 then estimate the value to 3 decimal places.

Answer 1

Answer:

The estimated value is 1.518

Step-by-step explanation:

Given

`\log_(11)38`

This is written in base 10 as follows:

`(log38)/(log11)=(1.580)/(1.041)=1.518`