Question

Find the area of the shaded region under the standard normal distribution to the left of the given z-score.Round your answer to four decimal places.-3-2-103412z = 1.56ZQP(Z < 1.56)=

Answer 1

0.9406

Explanation:

Given:

z = 1.56

Therefore we must calculate the following according to the graph:

`P\left(z<1.56\right)`

We calculate it by means of the table, just like this:

P(z < 1.56) = 0.9406